77x^2+96x+27=0

Solution for 77x^2+96x+27=0 equation:

77x^2+96x+27=0

a = 77; b = 96; c = +27;
Δ = b2-4ac
Δ = 962-4·77·27
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-30}{2*77}=\frac{-126}{154}
=-9/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+30}{2*77}=\frac{-66}{154}
=-3/7
$